* BUG in .TRAN statement? 
*
* When we put the variable at the increment time step, 
* you'll see the input reading difficulty error

.param  tstep=1u tend=10u tstart=2u
.tran   tstep tend start = tstart

* This is an error free code. 
*.tran  1u tend start=tstart 

v1      1 0     sin(0 1 1k)
r1      1 0     1

.print  tran    v(1)
.end